Showing posts with label Algebra help. Show all posts
Showing posts with label Algebra help. Show all posts

Tuesday, August 25, 2009

Word problem on percentage

a percentage is a way of expressing a number as a fraction of 100 (per cent meaning "per hundred"). It is often denoted using the percent sign, "%". For example, 45% (read as "forty-five percent") is equal to 45 / 100, or 0.45.let's see how to find percentage

Percentages are used to express how large one quantity is, relative to another quantity. The first quantity usually represents a part of, or a change in, the second quantity, which should be greater than zero. For example, an increase of $ 0.15 on a price of $ 2.50 is an increase by a fraction of 0.15 / 2.50 = 0.06. Expressed as a percentage, this is therefore a 6% increase.

Here is an example from sixth grade math word problems

Question:-

If a caterer receives an order for 2,800 canapes at 0.06 each and requires 30% down ,how much will the client owe after the deposit is paid?

Answer:-

Number of canapes = 2,800

cost of each canape= $0.06

Total amount = 2800 x 0.06=$168

Deposit amount = 30% of total amount

=30% of 168

= 30 x 168
--------- = 50.40
100

So the client owe $50.40 after the deposit paid.

Based on this ,we also know how to understand ratio word problems

Thursday, August 20, 2009

Solving linear equations

A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable.Linear equations can have one or more variables. Linear equations occur with great regularity in applied mathematics. While they arise quite naturally when modeling many phenomena, they are particularly useful since many non-linear equations may be reduced to linear equations by assuming that quantities of interest vary to only a small extent from some "background" state.We have linear equations with one variable and also linear equations in two variables


Let's see how to solve equations

To get math answers we need a step by step approach as follows


3x 6 4
---- = ----- = ----
x2-4 x2-4 x+2


3x 6 4
---- = -------- - ----
x2-4 (x+2)(x-2) x+2

1 6
= ---- x ---- - 4
x+2 x-2

3x 1 6-4(x-2)
----- = ---- x ----------
(x+2)x-2 x+2 x-2


3x= 14 - 4x

by adding 4x on both sides

7x = 14

divide by 2

x=2 is the answer

Wednesday, August 19, 2009

Divisibility by 11

Topic:Divisibility

Divisibility is a key concept in number theory. We say that an integer a is divisible by an integer b if there exists an integer c such that a=bc.

Test for divisibility by 11. Subtract the last digit from the remaining leading truncated number. If the result is divisible by 11, then so was the first number. Apply this rule over and over again as necessary.

A divisibility rule is a method that can be used to determine whether a number is evenly divisible by other numbers. Divisibility rules are a shortcut for testing a number's factors without resorting to division calculations. Although divisibility rules can be created for any base, only rules for decimal are given here.

Here is a example of a numeric and algebraic operations

Question:


Find the divisibility test of 11

Answer:




For more help on similar problems like this online tutor for math will guide you.